Showing posts with label Save images in Database. Show all posts
Showing posts with label Save images in Database. Show all posts

Wednesday, February 9, 2011

FileUpload Save Images in Database in ASP.NET C# VB.NET




Html markup of the page look like
<form id="form1" runat="server">
<div>
<asp:TextBox ID="txtName" runat="server" Width="95px">
</asp:TextBox>
<asp:FileUpload ID="FileUpload1" runat="server"/>
<asp:Label ID="lblMessage" runat="server">
</asp:Label>
<asp:Button ID="btnUpload" runat="server"
            OnClick="btnUpload_Click" Text="Upload"/>
</div>
</form>


C# Code behind
protected void btnUpload_Click(object sender, EventArgs e)
{
string strImageName = txtName.Text.ToString();
if (FileUpload1.PostedFile != null &&FileUpload1.PostedFile.FileName != "")
{
byte[] imageSize = new byte[FileUpload1.PostedFile.ContentLength];
HttpPostedFile uploadedImage = FileUpload1.PostedFile;
uploadedImage.InputStream.Read(imageSize, 0, (int)FileUpload1.PostedFile.ContentLength);
 // Create SQL Connection
SqlConnection con = new SqlConnection();
con.ConnectionString = ConfigurationManager.ConnectionStrings["ConnectionString"].ConnectionString;
// Create SQL Command
SqlCommand cmd = new SqlCommand();
cmd.CommandText = "INSERT INTO Images(ImageName,Image)" +" VALUES (@ImageName,@Image)";
cmd.CommandType = CommandType.Text;
cmd.Connection = con;
SqlParameter ImageName = new SqlParameter("@ImageName", SqlDbType.VarChar, 50);
ImageName.Value = strImageName.ToString();
cmd.Parameters.Add(ImageName);
SqlParameter UploadedImage = new SqlParameter("@Image", SqlDbType.Image, imageSize.Length);
UploadedImage.Value = imageSize;
cmd.Parameters.Add(UploadedImage);
con.Open();
int result = cmd.ExecuteNonQuery();
con.Close();
if (result > 0)
lblMessage.Text = "File Uploaded";
GridView1.DataBind();
}
}
VB.NET Code
Protected Sub btnUpload_Click(ByVal sender As Object, ByVal e As EventArgs)
Dim strImageName As String = txtName.Text.ToString()
If FileUpload1.PostedFile IsNot Nothing AndAlso
FileUpload1.PostedFile.FileName <> "" Then
Dim imageSize As Byte() = New Byte(FileUpload1.PostedFile.ContentLength - 1) {}
Dim uploadedImage__1 As HttpPostedFile =FileUpload1.PostedFileuploadedImage__1.InputStream.Read(imageSize, 0,CInt(FileUpload1.PostedFile.ContentLength))
' Create SQL Connection
Dim con As New SqlConnection()con.ConnectionString =ConfigurationManager.ConnectionStrings
("ConnectionString").ConnectionString
' Create SQL Command
Dim cmd As New SqlCommand()
cmd.CommandText = "INSERT INTO Images(ImageName,Image) VALUES (@ImageName,@Image)"
cmd.CommandType = CommandType.Text
cmd.Connection = con
Dim ImageName As New SqlParameter("@ImageName", SqlDbType.VarChar, 50)
ImageName.Value = strImageName.ToString()
cmd.Parameters.Add(ImageName)
Dim UploadedImage__2 As New SqlParameter("@Image", SqlDbType.Image, imageSize.Length)
UploadedImage__2.Value = imageSizecmd.Parameters.Add(UploadedImage__2)
con.Open()
Dim result As Integer = cmd.ExecuteNonQuery()
con.Close()
If result > 0 Then
lblMessage.Text = "File Uploaded"
End If
GridView1.DataBind()
End If
End Sub